Subnetting Question

[kammodo]

Hello, just opened the can of evil worms which is subnetting,
My question is this:

IP address 10.0.0.0 (class A)
Mask 255.255.240.0
Valid subnets 256-240=16
Subnets 4094
Hosts 4094
What would be the first valid Subnet address be? A) 10.0.16.0 - 10.0.32.0 - 10.0.48.0 ect or B) 10.16.0.0 – 10.32.0.0

Is the address set from left to right as in B or the other way around? Is there a rule of the thumb on this, or dosen’t it matter as they should have the same amount
of hosts and broadcasts on each?
Any help much appreciated
Thanks

[hbroomhall]

Originally Posted by kammodo

Hello, just opened the can of evil worms which is subnetting,
My question is this:

IP address 10.0.0.0 (class A)

If you are talking classes then the rules change.

Originally Posted by kammodo

Mask 255.255.240.0
Valid subnets 256-240=16
Subnets 4094

Eh? You have just said 16!

Originally Posted by kammodo

Hosts 4094

Counting how?

Originally Posted by kammodo

What would be the first valid Subnet address be? A) 10.0.16.0 - 10.0.32.0 - 10.0.48.0 ect or B) 10.16.0.0 – 10.32.0.0

Depends on how the router is set. Cisco allows 0 nets by default these days I believe, so neither is right. But A is closer. First IP is 10.0.0.0.

Originally Posted by kammodo

Is the address set from left to right as in B or the other way around? Is there a rule of the thumb on this, or dosen’t it matter as they should have the same amount
of hosts and broadcasts on each?

Don't understand this at all. There can never be the same number of hosts and broadcast addresses on a network!

Harry.

[Mr.Cheeks]

Struggling on Subnetting? Check this out!

[kammodo]

Sorry, I didn't explain myself properly.
I know you more than likley already know these basic caculations but these are my working outs for the problem.

Ip address 10.0.0.0
Mask 255.255.240.0

Bits used for subnets 12
Bits left over for host protion 12
Total avail subnets, 2 to the power of 12 -2 = 4094
Total avail hosts, 2 to the power of 12 -2 = 4094
Seperation between each subnet or first sub net ID 256-240=16 Which is my question, on what is the first subnet IP address? A) 10.0.16.0 - 10.0.32.0 - 10.0.48.0 ect or B) 10.16.0.0 – 10.32.0.0 -10.48.0.0 ect.
I understand that the first IP address is 10.0.0.0 the one that the rest of the world sees(router), its just the internal subnet IDs that I am having trouble with.
At the end I ment to say host numbers are the same as the subnet numbers not broadcast numbers which are obviously different (doh!).
Thanks for the help

[BrotherBill]

Your mask is 255.255.240.0. You still have to count the 0 in the second octate. Use 10.0.x.x

[kammodo]

Yes that does make sense.
Thanks for the reply

[BrotherBill]

Even though you're working with a class A address, you still have to consider the entire mask for your subnet addresses.

I agree with Mr. Cheeks. Be sure to check out the tutorials he pointed out. You'll find them a great learning tool. http://www.learntosubnet.com/

[kevicho]

Originally Posted by kammodo

Hello, just opened the can of evil worms which is subnetting,
My question is this:

IP address 10.0.0.0 (class A)
Mask 255.255.240.0
Valid subnets 256-240=16
Subnets 4094
Hosts 4094
What would be the first valid Subnet address be? A) 10.0.16.0 - 10.0.32.0 - 10.0.48.0 ect or B) 10.16.0.0 – 10.32.0.0

Is the address set from left to right as in B or the other way around? Is there a rule of the thumb on this, or dosen’t it matter as they should have the same amount
of hosts and broadcasts on each?
Any help much appreciated
Thanks

It Should be a, as it will run from 10.0.0.0 which is the network address to 10.0.15.255 which is the broadcast address for the first subnet.

You always use the first octet which is not full (ie 255) to set the octet to be used for dividing the subnets (im sure that sounded easier in my head to explain lol), thus here 255.255.240.0 has the 3rd octet used for the host/subnet octet, as we see below

table for this network
1) 10.0.0.0 - 10.0.15.255
2) 10.0.16.0 - 10.0.31.255
3) 10.0.32.0 - 10.0.47.255
4) 10.0.48.0 - 10.0.65.255

and so on

Subnetting gets easier as you read through it, also you need to remember to stop at how many subnets you create, for example if you switch from a 19 to a 21 cidr network, then you have created 4 subnets, which means that 66.0 - 73.255 is outside the range.

The microsoft press book is great for this section

[kammodo]

Thankyou all for the help. Im sure ill be pulling my hair out, on the next ccna chapter.