70-270 Difficulty...

[Gingerdave]

Originally Posted by Modey

. There is a reason it's called 'The Beast' you know.

Because the use it as a story to scare unwary MS cert takers?

[Ergath]

Right, I'm doing well, within my first three posts on the forum I've demeaned the efforts of legions of 70-291 MCPs

I'll shut up until I've taken the exam then

[jk2447]

Originally Posted by Ergath

Right, I'm doing well, within my first three posts on the forum I've demeaned the efforts of legions of 70-291 MCPs

I'll shut up until I've taken the exam then

Ha ha no you haven't mate We just don't want you to take 291 lightly if you pass 270 and 290. Thats exactly what I did

[Modey]

Originally Posted by Ergath

Right, I'm doing well, within my first three posts on the forum I've demeaned the efforts of legions of 70-291 MCPs

I'll shut up until I've taken the exam then

Heh, not at all. It's just a very tough exam that's all. Wouldn't want you to start crying when you start to read the book.

[nXPLOSi]

Thanks for all the feedback on the exam guys, its been helpful.

I've watched a few CBT's on the security area in which I was weak, but felt I knew most of what was being said so im going to reread the chapter in the sybex book tonight and see how I get on with that. I am actually looking forward to the exam on Saturday now, cant wait to get in there.

Thanks for the support and best wishes

[Daniel]

One thing I would say, is that ignore the TCP/IP section of 70-291, it asks you to memorize the table of Subnet Mask Notations.

There is a much simpler way to do it.

Example:

192.168.1.24 /28

This gives us a subnet mask of 255.255.255.240

So, of course in binary form this is:

11111111.11111111.11111111.11110000

So, the way I learned from Cisco how to find out what the subnet mask is with the /n notation is this:

The first digit in an octet represents 128, the second, 64.

Here is how it works..

1st > 128
2nd > 64
3rd > 32
4th > 16
5th > 8
6th > 4
7th > 2
8th > 1

So now we know what the values are for the ascending 1's in the octet.

Now we can use this instead of memorizing the Subnet Mask Notation table.

11111111 = 255
11111111 = 255
11111111 = 255
11110000 = 240

You get 240 because you're 'adding up' the 1's

128 + 64 + 32 + 16 = 240

You get 255 because:

128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = 255

That's how I do it, sorry if it's not explained clearly but this was done on the fly

[Qs]

Originally Posted by Daniel

One thing I would say, is that ignore the TCP/IP section of 70-291, it asks you to memorize the table of Subnet Mask Notations.

There is a much simpler way to do it.

Example:

192.168.1.24 /28

This gives us a subnet mask of 255.255.255.240

So, of course in binary form this is:

11111111.11111111.11111111.11110000

So, the way I learned from Cisco how to find out what the subnet mask is with the /n notation is this:

The first digit in an octet represents 128, the second, 64.

Here is how it works..

1st > 128
2nd > 64
3rd > 32
4th > 16
5th > 8
6th > 4
7th > 2
8th > 1

So now we know what the values are for the ascending 1's in the octet.

Now we can use this instead of memorizing the Subnet Mask Notation table.

11111111 = 255
11111111 = 255
11111111 = 255
11110000 = 240

You get 240 because you're 'adding up' the 1's

128 + 64 + 32 + 16 = 240

You get 255 because:

128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = 255

That's how I do it, sorry if it's not explained clearly but this was done on the fly

Very similar method to how I originally learnt...

I used to just write the numbers over the octet though. It's easier to view like this :-

E.G.







Qs

[nXPLOSi]

Yeah I use the same method as yourself Qs, as taught by the MS Course at QA, formally xpertise, in London.

[Daniel]

Ah, sorry, I couldnt explain it much better, plus I wanted to give a bit of background instead of just diving in.

Apologies

[Qs]

Originally Posted by Daniel

Ah, sorry, I couldnt explain it much better, plus I wanted to give a bit of background instead of just diving in.

Apologies

Don't apologise Your explanation was good!

It's just easier to view if you write it down in a different format.

If it helps people, it's always good.

+rep for your original post.

Qs

[Daniel]

Originally Posted by Qs

Don't apologise Your explanation was good!

It's just easier to view if you write it down in a different format.

If it helps people, it's always good.

+rep for your original post.

Qs

Thanks Qs

Was just worried I had given a much more garbled answer than needed !

Dont wanna throw anyone off course !

Hope someone finds the above posts useful ^^

[Lucinda]

Don't worry! It's not hard! Trust yourself!

[Ence]

bin table starts at 1 I did think it started from 2.

256 128 64 32 16 8 4 2

I also learnt by bits borrowed.

128 |1
192 |2
224 |3
240 |4 - Qs
248 |5
252 |6
254 |7
255 |8

[drum_dude]

Originally Posted by Modey

I can confirm that 'yes' you are wrong. Well the 290 ain't so bad, but the 291 is damn tough. There is a reason it's called 'The Beast' you know.

Best book for 70-270 is the XP Resource Kit, yes huge book but it contains the many best practices that the others do not have and which feature a lot on the exam. I failed 70-270 first time round and I used the traning kit and the Exam Cram 2 book. Second time around I made sure that I'd backed up my knowledge by looking up the areas covered by the exam in the Resource Kit...well I flew through the exam with a score of over 900 if I remember correctly. First attempt I got 675 :o(

[drum_dude]

Originally Posted by drum_dude

Best book for 70-270 is the XP Resource Kit, yes huge book but it contains the many best practices that the others do not have and which feature a lot on the exam. I failed 70-270 first time round and I used the traning kit and the Exam Cram 2 book. Second time around I made sure that I'd backed up my knowledge by looking up the areas covered by the exam in the Resource Kit...well I flew through the exam with a score of over 900 if I remember correctly. First attempt I got 675 :o(

Oops, didn't realise this was an old post lol!